1137. N-th Tribonacci Number
Easy | DP | 24 ms (94.39%), 14.2 MB (43.64%)
Source: LeetCode - N-th Tribonacci Number GitHub: Solution / Performance
The Tribonacci sequence Tn is defined as follows:
T0 = 0, T1 = 1, T2 = 1, and Tn+3 = Tn + Tn+1 + Tn+2 for n >= 0.
Given n
, return the value of Tn.
class Solution:
def tribonacci(self, n: int) -> int:
# (base case)
if n == 0: return 0
if n == 1: return 1
if n == 2: return 1
# ==================================================
# Dynamic Programming =
# ==================================================
# time : O(n)
# space : O(1)
first, second, third = 0, 1, 1
for i in range(n - 2):
ans = first + second + third
first = second
second = third
third = ans
return third
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